Alright so, I'm trying to take the integral of 3/2 / (u^2 + 3/4)(adsbygoogle = window.adsbygoogle || []).push({});

according to the book the answer is sqrt(3) * arctan(2u/sqrt(3))

but when I try to get the integral I get: 2*arctan(2u/sqrt(3)) -- I don't see any way to take a sqrt(3) out of the function.

The graphs look about the same except they are shifted vertically apart. Is this just a constant issue (are the answers basically equivilent)? Or did I mess up my algebra?

1

[tex]

\frac{3/2}{u^2+3/4}

[/tex]

2

[tex]3/2 * \frac{1}{(4u^2+3)/4}[/tex]

3

[tex]3/2*4 * \frac{1}{4u^2+3}[/tex]

4

[tex]6* \frac{1}{3(4/3u^2+1)}[/tex]

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Arctan integral

**Physics Forums | Science Articles, Homework Help, Discussion**