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Arctan integral

  1. Jul 8, 2008 #1
    Last edited by a moderator: Apr 23, 2017
  2. jcsd
  3. Jul 8, 2008 #2

    arildno

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    Well..perhaps along these lines:
    [tex]k^{2}\equiv{y}^{2}+a^{2}, x=kSinh(u)\to\sqrt{x^{2}+y^{2}+a^{2}}=k\Cosh(u), dx=kCosh(u)du[/tex], whereby our integral should roughly be something like:
    [tex]\int\frac{kdu}{a^2+k^{2}Sinh^{2}(u)}[/tex]
    Maybe.
     
  4. Jul 12, 2008 #3
    bump :wink:
     
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