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[tex]y=tan^{-1}\left(\frac{1}{ln(x)}\right)[/tex]

[tex]y'=\frac{1}{1-\left(\frac{1}{ln(x)}\right)^2}[/tex]

[tex]y'=\frac{1}{1-(lnx)^{-2}}[/tex]

is this correct?

do I have to take into account the derivative of [itex]\frac{1}{ln(x)}[/itex]?

if I do, what is the derivative of [itex]\frac{1}{ln(x)}[/itex]?

[tex]y'=\frac{1}{1-\left(\frac{1}{ln(x)}\right)^2}[/tex]

[tex]y'=\frac{1}{1-(lnx)^{-2}}[/tex]

is this correct?

do I have to take into account the derivative of [itex]\frac{1}{ln(x)}[/itex]?

if I do, what is the derivative of [itex]\frac{1}{ln(x)}[/itex]?

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