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Homework Help: Arctan question

  1. Jan 21, 2010 #1
    [tex]-\frac{\pi}{4}=arctan(\frac{\frac{-2L}{3}}{R})\\[/tex]

    why it equals
    [tex]\frac{\frac{-2L}{3}}{R}=-1[/tex]

    ?
     
    Last edited: Jan 21, 2010
  2. jcsd
  3. Jan 21, 2010 #2
    [math]-\frac{\pi}{4}=arctan(\frac{\frac{-2L}{3}}{R})\\[/math]

    why it equals
    [math]\frac{\frac{-2L}{3}}{R}=-1[/math]
     
  4. Jan 21, 2010 #3

    Mark44

    Staff: Mentor

    Take the tangent of both sides.
     
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