1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Are you good at equations?

  1. Jan 6, 2006 #1
    I need to prove how 1 ohm is equal to
    1 J/C*A
    -
    J being Joules
    C being coulombs
    A being Amperes
    -
    So far I got this, tell me if i'm going in the right track.
    -
    1 J/C*A -- 1 kg*m/s^2 over C and A
    -
    Now how can I do the rest knowing that you can find an ohm by the equation R = p*L/A? I know that a coulomb is the inverse of 6.24*10^18 and its 1 A*s.
     
  2. jcsd
  3. Jan 6, 2006 #2
  4. Jan 7, 2006 #3
    Okay so i know 1 Ω = 1 V/A = 1 m2·kg·s–3·A–2
    so...
    1 kg*m/s^2 over CA

    C = A*S

    But why is 1 Ω = 1 V/A = 1 m2·kg·s–3·A–2 has "...s–3·A–2?" That's what I'm confused about. Can someone break it down for me?
     
  5. Jan 8, 2006 #4
    1 V = 1 J/C = 1 kg.m2.s-2.C-1

    Since 1 A = 1 C/s,

    1 V = 1 kg.m2.s-3.A-1
     
  6. Jan 8, 2006 #5
    Oh! Now i see the picture! Thank you:smile:
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?