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## Homework Statement

This is so basic and yet I'm not getting it.

Find the volume of the solid when the region enclosed is revolved arond the y axis.

[tex] x = \sqrt{1 + y}[/tex]

x=0, y=3

## Homework Equations

## The Attempt at a Solution

So I first graphed the thing, finding that the enclosed area was between y=1 and y=3. I took the volumne of the equation, or A=pi *[tex]\sqrt{1 + y}^2[/tex]. I then took the integral, pi * [tex]\int_{1}^{3} 1 + y dy[/tex], coming out with 6*pi. My book says this isn't right. Did I do anything wrong? Use the wrong formula?

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