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Calculus and Beyond Homework Help
Area between 2 polar equations
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[QUOTE="Zack K, post: 6122869, member: 586916"] [h2]Homework Statement [/h2] Find the area of the region that lies inside the first curve and outside the second curve. ##r=6## ##r=6-6sin(\theta)## [h2]Homework Equations[/h2] ##A=\frac {1} {2}r^2\theta## [h2]The Attempt at a Solution[/h2] \[/B] If I'm correct, the area should just be ##\frac {1} {2}\int_{0}^{2\pi} 6^2 d\theta - \frac {1} {2}\int_{0}^{2\pi} (6-6sin(\theta))^2 d\theta##. If that's the case then I'm probably making simple error calculating it. EDIT: I just realized by graphing that the range is between π to 2π. How would I figure that out? Would it be just by setting both equations equal and finding intercepts? [/QUOTE]
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Area between 2 polar equations
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