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Find the are between the curve [tex] y=\sqrt{1-x} [/tex] and the coordinate axes
I do believe this integral is equivalent to the one I posted. But how does your integral follow from the problem?Originally posted by himanshu121
Why you need a substitution
[tex]\int_{0}^{1}\sqrt{1-x}d(1-x)[/tex]
It should beOriginally posted by himanshu121
[tex]\int_{0}^{1}\sqrt{1-x}d(1-x)[/tex]