1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Area between curve and axes

  1. Dec 11, 2003 #1
    Find the are between the curve [tex] y=\sqrt{1-x} [/tex] and the coordinate axes
  2. jcsd
  3. Dec 11, 2003 #2


    User Avatar
    Science Advisor
    Homework Helper

    Do you know integral calculus?
  4. Dec 12, 2003 #3


    User Avatar
    Science Advisor

    I think it would be f(max) - f(min) where f(x) = (2/3)(1 - x)^(3/2)
  5. Dec 12, 2003 #4
    You have to perform the integral
    Try the substitution u=1-x
  6. Dec 12, 2003 #5
    First find the domain and range that will give u limits of integration

    Why you need a substitution

  7. Dec 12, 2003 #6
    I do believe this integral is equivalent to the one I posted. But how does your integral follow from the problem?
  8. Dec 12, 2003 #7
    I was just shortening the step which are required for substitutions

    Anyway i will be thinking that way too which u have asked
  9. Dec 12, 2003 #8
    In order to do this problem, we usually take the following steps.
    1. Sketch the curve [tex] y=\sqrt{1-x} [/tex] and find out what exactly you need to find.

    2. Find the x-intercept(s) or y-intercept(s).

    3. Write down a definite integral and solve the problem.

    In this case, the x-intercept is 1, so you can find out the area by [tex]\int_{0}^{1}\sqrt{1-x}dx[/tex]

    It should be
  10. Dec 12, 2003 #9
    Area is positive so in any case it is modulus
    of the integral
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook