1. The problem statement, all variables and given/known data Find the area inside one loop of r = 2cos(3 theta) and outside the circle r = 1 2. Relevant equations 3. The attempt at a solution I need to clarify something about the limits of integration. I found the intersection of the two curves to be at an angle of pi/9. This is how I setup my integral A = 2*integral from 0 to pi/9 of 1/2(2cos(3 theta))^2 d theta Is it correct ?