- #1

- 402

- 0

[tex]y=sin \frac{\pi x}{2}[/tex]

and

[tex]y=x[/tex]

how do i find the boundaries?

- Thread starter suspenc3
- Start date

- #1

- 402

- 0

[tex]y=sin \frac{\pi x}{2}[/tex]

and

[tex]y=x[/tex]

how do i find the boundaries?

- #2

- 402

- 0

EDIT:i know how to get the boundaries, but how do i know what numbers to integrate between?

- #3

arildno

Science Advisor

Homework Helper

Gold Member

Dearly Missed

- 9,970

- 132

Eeh, what about the interval [itex]0\leq{x}\leq{1}[/itex]??

- #4

- 402

- 0

why between 0 and 1

?..also..what is the integral of sin2x?

?..also..what is the integral of sin2x?

- #5

- 402

- 0

- #6

arildno

Science Advisor

Homework Helper

Gold Member

Dearly Missed

- 9,970

- 132

Answer that, and you automatically may set up an equation whose solutions are the points of intersection.

- #7

- 590

- 0

You may graph the function for clearer understanding .

- #8

- 402

- 0

making it [tex]\frac{2y}{sin \pi} = x[/tex] is wrong isnt it?

how do i isolate x?

If I can find the points where the two curves intersect, then I can integrate between these two points to find the Area

- #9

- 590

- 0

You have two equations in y and x .

The point of intersection has to satisfy both the conditions .

Now can you form the equation ?

Hint : Try to get an equation in x alone .

- Last Post

- Replies
- 2

- Views
- 5K

- Last Post

- Replies
- 4

- Views
- 924

- Last Post

- Replies
- 10

- Views
- 709

- Last Post

- Replies
- 4

- Views
- 4K

- Last Post

- Replies
- 6

- Views
- 2K

- Last Post

- Replies
- 6

- Views
- 2K

- Last Post

- Replies
- 6

- Views
- 1K

- Last Post

- Replies
- 3

- Views
- 3K

- Last Post

- Replies
- 2

- Views
- 877

- Last Post

- Replies
- 2

- Views
- 5K