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Homework Help: Area between two curves

  1. Sep 25, 2006 #1
    I am trouble with problems that don't list each function f(x) or g(x). The book sets them equal to y. Every time I do these I'm getting them wrong. When I check the solution, I'm mistaking f(x) for g(x) or vise versa. So is there a way to tell which y is f(x) or g(x)?
  2. jcsd
  3. Sep 25, 2006 #2
    An example might help be helpful.
  4. Sep 25, 2006 #3


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    I can't say I understood your question, but refering to the title of the thread, the area between two 'well-behaved' functions f and g on the interval [a, b] is given with [tex]\int_{a}^b(f(x)-g(x))dx[/tex], if f(x) >= g(x), for every x from [a, b].
  5. Sep 26, 2006 #4


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    Of course, the region "ends" where the two curves cross- that is, they have the same y value for that x value. That's why your book "sets them equal to y"- to determine the y values where they cross and thus the limits of integration.
    A little hint- if you area comes out negative, then you have the two curves in the wrong order!
  6. Sep 26, 2006 #5
    This is what I'm talking about:

    Find the area between these two curves-

    Now how do you know which is f(x) or g(x)?
  7. Sep 27, 2006 #6


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    What? Neither is "f(x)" or "g(x)" until you name them! Call whichever you want f and the other g. It might be that your textbook is using a convention that "f" is always the "upper" curve and "g" is always the "lower" curve so that the area is given by [itex]\int (f(x)- g(x))dx[/itex]. If that is the case, then determine which is above the other. Hint: the first is a parabola opening upward, the second a parabola opening downward. You need to decide which is the "upper" curve and which the "lower" curve. You will also need to determine where they intersect.
  8. Sep 27, 2006 #7
    I swear when I worked that problem out it only worked one way. Off the top of my head I had f(x) switched with what the book said. My way was wrong, but then I switched my f(x) for the books way I got the problem right. Had someone double check my math both times and it was good. Thanks for the help!
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