Compute the area between the graphs of f(x) = 8sin(2x) and g(x) = 5sin(x)+3sin(2x) on the interval [0,pi/2]
Area = Integral of [f(x)-g(x)]dx
The Attempt at a Solution
I first did f(x) - g(x) = 5sin(2x)-5sin(x)...after integrating, I got -5/2cos(2x)+5cos(x). Using pi/2 as the upper bound and 0 as the lower bound, I did the calculations but the answer wasn't right. Could someone please point out where I made a mistake?
Thank you very much!