# Homework Help: Area enclosed by polar curve

1. Apr 19, 2012

### amninder15

Can someone please help me on this question. I tried to solve it by integrating 0.5*(1-3sin(θ)^2 from -Pi/2 to 0 but I didnt get the answer.

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2. Apr 19, 2012

### LCKurtz

Why did you choose $-\frac \pi 2$ to $0$? Just guessing? Have you drawn a sketch? Do you know what $\theta$ give negative $r$ values for the inner loop?

3. Apr 19, 2012

### amninder15

Yea I made some silly mistake I think It goes from sin^-1(1/3) to Pi-sin^-1(1/3). But that looks ugly. Am I on right path.

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4. Apr 19, 2012

### sharks

Your graph is correct for $\theta$ varies between 0 and 2pi. Now, generally how do you find the area of a polar region?

5. Apr 19, 2012

### LCKurtz

Yes. Those are the correct limits. Ugly or not, just plow ahead and you will get one of the answers listed.