Area finding equality

There is a graph associated to it. Please look at the screenshot.

Ok, so, here is my process.
I modeled the three functions.
y=x
y=1/a^2 x
and y=1/x

Then, I calculated A using calculus. (Integrals)
Integral of x-1/a^2 x from 0 to 1 + integral of 1/x-1/a^2 x from 1 to a
A=1-1/a^2

Now, how is a=e^A?
 

Attachments

LCKurtz

Science Advisor
Homework Helper
Gold Member
9,404
676
There is a graph associated to it. Please look at the screenshot.

Ok, so, here is my process.
I modeled the three functions.
y=x
y=1/a^2 x
and y=1/x

Then, I calculated A using calculus. (Integrals)
Integral of x-1/a^2 x from 0 to 1 + integral of 1/x-1/a^2 x from 1 to a
Correct integral setups.

A=1-1/a^2
Wrong answer. Recheck your integration or show us your steps.
 

The Physics Forums Way

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving
Top