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Area finding equality

  1. Mar 30, 2014 #1
    There is a graph associated to it. Please look at the screenshot.

    Ok, so, here is my process.
    I modeled the three functions.
    y=x
    y=1/a^2 x
    and y=1/x

    Then, I calculated A using calculus. (Integrals)
    Integral of x-1/a^2 x from 0 to 1 + integral of 1/x-1/a^2 x from 1 to a
    A=1-1/a^2

    Now, how is a=e^A?
     

    Attached Files:

  2. jcsd
  3. Mar 30, 2014 #2

    LCKurtz

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    Correct integral setups.

    Wrong answer. Recheck your integration or show us your steps.
     
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