There is a graph associated to it. Please look at the screenshot. Ok, so, here is my process. I modeled the three functions. y=x y=1/a^2 x and y=1/x Then, I calculated A using calculus. (Integrals) Integral of x-1/a^2 x from 0 to 1 + integral of 1/x-1/a^2 x from 1 to a A=1-1/a^2 Now, how is a=e^A?