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Area Moment of Inertia

  1. Mar 25, 2009 #1
    Okay, maybe I am retarded, but i am having trouble with this.

    i need to find the equivalent spring constant K of a shaft with radius=r, length=l, and modulus of rigidity=G

    I know that K=GJ/l

    Question 1) Is J in this case the AREA moment of inertia? I think it is.

    Question 2) Why can't I find online a formula for the J of a shaft?

    I know the cross section is simply a circle and it is rotating about
    a point passing through its center and perpendicular to the plane of the circle

    I do not have a mechanics book with me (at work). Can anyone help me out here?

    Thanks!
     
  2. jcsd
  3. Mar 25, 2009 #2

    PhanthomJay

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    J is the Area Polar moment of inertia (axis thru center along the longitudinal axis, perpendicular to circle cross section); J = I_x +I_y
    You didn't Google hard enough. J = (pi)d^4/32 for a solid circular shaft.
     
  4. Mar 26, 2009 #3
    Thanks PJ. My book is silly. For vibrations it uses J as the mass moment of inertia whereas the usual convention is I and J is area so I was all inds of confused.
     
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