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Area of a region intergral

  1. Jan 20, 2009 #1
    1. The problem statement, all variables and given/known data
    decide whether to integrate with respect to x or y. draw a typical approximating rectangle and label its height and width then find the aread of the region

    X^2 = y, x-2y = 3

    3. The attempt at a solution
    i'm not sure how to find if the questions should be repsect to x or y
    i tried doing it with respect to X I did it with integral with upper bound being 9 and lower 0 and i plugged in rad x + (x-3)/2 dx and got 45 -4 and the answer is 32/3
  2. jcsd
  3. Jan 20, 2009 #2


    Staff: Mentor

    Did you draw a graph of the region? The graphs of the functions you gave don't intersect, so they don't determine a region, so you're going to have a tough time finding its area.

    Have you posted the right equations?
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