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## Homework Statement

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region.

2y=3(x^1/2)

y=4

2y+4x=7

## Homework Equations

## The Attempt at a Solution

I decided to solve for y, since that would make it easier to graph. This got me y=(3(x^1/2)/2) and y=7/2-2x. I then graphed these, finding that the span on the x-axis would be from 0 to 2.

I integrated the problem, getting 3-2*(2^1/2). This seems wrong. What happened? I'm probably overlooking something small...

(By the way, Latex isn't working, so the x^1/2 things means that that number or variable is square rooted.

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