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Area of a Truncated Ellipse

  1. Mar 24, 2015 #1
    Does anyone know how to find the area of an intersection between a cylinder of height 8 and radius 6 and a plane that passes through the cylinder, forming a chord of 10 units at the top and bottom faces of the cylinder? The area of intersection curves with the cylinder, forming a truncated ellipse, not a rectangle. I'm thinking you could divide the truncated ellipse into a rectangle and two sections of a circle, and find the rectangle by pretending the two chords are opposite edges of a rectangular prism, but I don't know how to find the width of the prism. Can anyone help?
     
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  3. Mar 24, 2015 #2

    RUber

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    First find the length of the perpendicular bisector from the center to the chord using Pythagorean thm.
    Then find the width of the circle based on distance from the center (r cos).
    Then find the distance from center (height) based on position in z. (linear)
     
  4. Mar 25, 2015 #3
    Ok so I figured out the area of the rectangle, 60 sqrt 3, and I know that the height of each semi-ellipse is 1, and their length is 6 sqrt 3, so how would I find the areas of the two semi-ellipses?
     
  5. Mar 25, 2015 #4

    RUber

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    area of an ellipse is ##\pi a b ## where a is minor semi-axis and b is major semi-axis.
     
  6. Mar 25, 2015 #5

    RUber

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    What if you recast width in terms of theta where theta goes from ## -sin^{-1}\frac{\sqrt 11}{6}## to ##sin^{-1}\frac{\sqrt 11}{6}##?
    then you will have an integral
    ## \int_{-sin^{-1}\frac{\sqrt 11}{6}} ^{sin^{-1}\frac{\sqrt 11}{6}} width(\theta)length(\theta)d\theta##.
     
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