# Area of an enclosed region

## Homework Statement

Find the area of the region enclosed by y = $$\sqrt[3]{x}$$, the tangent line to this curve at x = 8, and the y-axis.

## Homework Equations

Definate integral properties, fundamental theorem of calculus

## The Attempt at a Solution

I know and understand what the question is asking for--find the area of the region--i'm just having problems actually finding the region I need to calculate. I can't seem to figure out what they want through the tangent line; do I need to simply take the derivative of $$\sqrt[3]{x}$$ and use it, plug in x=8 into the derivative and then use it, or do something completely different? Any help you can guys can give to point me in the right direction here would be greatly appreciated, thanks in advance.

## Answers and Replies

Related Calculus and Beyond Homework Help News on Phys.org
HallsofIvy
Homework Helper
It might be easier if you think of the function as x= y3. Then dx/dy= 3y2 so dy/dx= 1/(3y). Now what is y when x= 8?

Cyosis
Homework Helper
Find the equation for the tangent line, then draw both the tangent line and y on the same axes. It will be obvious from there which region you want to calculate.

It will look like this:

http://img29.imageshack.us/img29/32/region.jpg [Broken]

Last edited by a moderator: