- #1

- 1

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r[tex]^{2}[/tex] = 9cos(5[tex]\vartheta[/tex])

I picked the inteval from 0 to [tex]\pi[/tex]/2 and I keep getting 18/5 but the back of the book says the answer is 18. I think something is wrong with my interval. Help Please!

- Thread starter schaefer
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- #1

- 1

- 0

r[tex]^{2}[/tex] = 9cos(5[tex]\vartheta[/tex])

I picked the inteval from 0 to [tex]\pi[/tex]/2 and I keep getting 18/5 but the back of the book says the answer is 18. I think something is wrong with my interval. Help Please!

- #2

- 17

- 0

Try drawing out the curve.Note, cos(5*angle) must be > 0 to give a real point on the curve.

when angle=0, r=3

when angle=18 degree, r=0

hope this is helpful

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