Area of polar curves

  • Thread starter itzela
  • Start date
  • #1
itzela
34
0
I am having trouble finding the area between 2 polar curves... I have the procedure down, but the bounds are throwing me off. Any help with understanding how to bound would be great appreciated!

I have attatched one problem that I am having hard time with and the work I have done. I know that I am doing something wrong because I am getting a negative number for an area (which shouldn't be).
 

Attachments

  • problem.JPG
    problem.JPG
    20.2 KB · Views: 417

Answers and Replies

  • #2
lurflurf
Homework Helper
2,457
154
You can't write that as one integral in that way. The Functions do not respond to the parameters the same way, different bounds are needed for each.
[tex]\frac{A}{2}=\frac{1}{2}\int_{\frac{\pi}{3}}^{\pi}(1+\cos(\theta))^2 d\theta - \frac{1}{2}\int_{\frac{\pi}{3}}^{\frac{\pi}{2}}(3\cos(\theta))^2 d\theta[/tex]
 
Last edited:
  • #3
itzela
34
0
Thanks :smile:
After working on it for a little while i arrived at the same expression... and i was a little unsure about it, but you confirmed it!
 

Suggested for: Area of polar curves

Replies
2
Views
233
  • Last Post
Replies
2
Views
429
  • Last Post
Replies
2
Views
615
Replies
33
Views
1K
  • Last Post
Replies
0
Views
281
Replies
2
Views
447
Replies
2
Views
1K
  • Last Post
Replies
2
Views
529
Top