Area of polar curves

  • Thread starter itzela
  • Start date
  • #1
34
0
I am having trouble finding the area between 2 polar curves..... I have the procedure down, but the bounds are throwing me off. Any help with understanding how to bound would be great appreciated!

I have attatched one problem that I am having hard time with and the work I have done. I know that I am doing something wrong because I am getting a negative number for an area (which shouldn't be).
 

Attachments

Answers and Replies

  • #2
lurflurf
Homework Helper
2,432
132
You can't write that as one integral in that way. The Functions do not respond to the parameters the same way, different bounds are needed for each.
[tex]\frac{A}{2}=\frac{1}{2}\int_{\frac{\pi}{3}}^{\pi}(1+\cos(\theta))^2 d\theta - \frac{1}{2}\int_{\frac{\pi}{3}}^{\frac{\pi}{2}}(3\cos(\theta))^2 d\theta[/tex]
 
Last edited:
  • #3
34
0
Thanks :smile:
After working on it for a little while i arrived at the same expression.... and i was a little unsure about it, but you confirmed it!
 

Related Threads on Area of polar curves

  • Last Post
Replies
1
Views
4K
Replies
6
Views
2K
Replies
15
Views
1K
Replies
2
Views
4K
Replies
7
Views
6K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
16
Views
13K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
2
Views
6K
Top