# Area of polar curves

I am having trouble finding the area between 2 polar curves..... I have the procedure down, but the bounds are throwing me off. Any help with understanding how to bound would be great appreciated!

I have attatched one problem that I am having hard time with and the work I have done. I know that I am doing something wrong because I am getting a negative number for an area (which shouldn't be).

#### Attachments

• 20.2 KB Views: 362

lurflurf
Homework Helper
You can't write that as one integral in that way. The Functions do not respond to the parameters the same way, different bounds are needed for each.
$$\frac{A}{2}=\frac{1}{2}\int_{\frac{\pi}{3}}^{\pi}(1+\cos(\theta))^2 d\theta - \frac{1}{2}\int_{\frac{\pi}{3}}^{\frac{\pi}{2}}(3\cos(\theta))^2 d\theta$$

Last edited:
Thanks
After working on it for a little while i arrived at the same expression.... and i was a little unsure about it, but you confirmed it!