The shorter sides of a right-angled triangle are of length (x+y)cm, (x-y)cm respectively. Given that the length of the hypotenuse is [tex]\sqrt68[/tex]cm and that the area of the triangle is [tex]8cm^2[/tex], find x and y.(adsbygoogle = window.adsbygoogle || []).push({});

[tex]\displaystyle{(x+y)^2 + (x-y)^2 = (\sqrt68)^2}[/tex]

[tex]\displaystyle{x^2+y^2=34}[/tex] ----------- (1)

[tex]\displaystyle{\frac{1}{2}(x+y)(x-y)=8}[/tex]

[tex]\displaystyle{x^2+y^2=16}[/tex] ----------- (2)

I can't seem to solve it. Did I do something wrong?

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# Homework Help: Area of the triangle math

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