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Area of Thermal Expansion

  • Thread starter vkt420
  • Start date
  • #1
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Homework Statement


A non-isotropic material is heated, fractional increase in length is different along different directions. With length l1=6.1 cm and l2=6.0 cm. In direction of l1, the coefficient expansion is [itex]\alpha[/itex]1= 10×10-5 K-1 and direction l2 is [itex]\alpha[/itex]2= 40×10-5K-1. The plate is heated until it becomes a perfect square. What is the area of the square? (The answer is 38 cm2) I just don't know how use the equations with out a given temperature.


Homework Equations


ΔL=[itex]\alpha[/itex]L0T
Lx=Lx0+Lx0[itex]\alpha[/itex]ΔT
Ly=Ly0+Ly0[itex]\alpha[/itex]ΔT
A0=Lx0Ly0
A=LxLy

The Attempt at a Solution


Not sure what to do with the equations without the temperature.
 

Answers and Replies

  • #2
6,054
390
You need to find the temperature from the condition that the rectangular becomes square.
 

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