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- Thread starter maxkor
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jonah1

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Please show us what you have tried and exactly where you are stuck.In triangle ABC $AC=BD, CE=2, ED=1, AE=4$ and $\angle CAE=2 \angle DAB$. Find area ABC.

We can't help you if we don't where you are stuck.

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HOI

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How did you get those?

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maxkor

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Geogebra...

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mrtwhs

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Continuing to use the law of cosines we get $AD=\dfrac{3\sqrt{10}}{2}$ and $AB=3\sqrt{6}$.

Finally, using the law of cosines on $\triangle ABD$ we get $\alpha \approx 71.170769^{\circ}$.

Your diagram is incorrect.

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