Given 80 feet of fencing, what is the maximum area that you can enclose along a wall?(adsbygoogle = window.adsbygoogle || []).push({});

Solution:

L=lenght, W=width, A=area

2L+2W=80 (perimeter) ==> L+W=40 ==> L=40-W

LW=A ==> (40-W)(W)= -W^2+ 40W= A

(dA/dW)=0=-2W+40=0 ==> W=20

W=20, L=20--------------------------------------------------ANSWERS

Is this right? any input would be appreciated.

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# Area optimization problem

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