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- Thread starter vabamyyr
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- #2

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Did you mix up alpha and beta? (check the angles in the equations)

- #3

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on the image alfa and beta were mixed up but corrected now

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Hello, I am linguist teacher, I am sorry for posting in your thread, because I really don't know how to start a thread, I have got a problem in math class, i take it as my second degree, very basic but i don't know how to solve it

I have a big square with one point(x,y) inside it, i have tow other small rectangles, with a given width (B), the two rectangles are drawn, divided with lines, into very small squares, then I put one head of one rectanguler into the square at one edge of the square, and the other rectangler is done the same but from the opposite edge, such that the point is on the line from rectanguler to other rectaguler.

But not all rectangler width is inside the square. If i know how many the very small squares in the 2 rectagulers are inside the big square, How can i find the centroid of the big square ?

Thanks a bunch

I have a big square with one point(x,y) inside it, i have tow other small rectangles, with a given width (B), the two rectangles are drawn, divided with lines, into very small squares, then I put one head of one rectanguler into the square at one edge of the square, and the other rectangler is done the same but from the opposite edge, such that the point is on the line from rectanguler to other rectaguler.

But not all rectangler width is inside the square. If i know how many the very small squares in the 2 rectagulers are inside the big square, How can i find the centroid of the big square ?

Thanks a bunch

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- #5

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can someone help me please ?

- #6

rachmaninoff

vabamyyr said:i started to work on a problem. A point on a plane is away from 3 sequential tips...

To find the area, it would be enough to find the lengths of DC and CB, wouldn't it?

You're familiar with the theorem of cosines:

You know EC, EB, and α - can you find CB?

You know @, #, and (α + β) - can you find DC?

Neat spelling of α - is that Estonian?alfa and beta

- #7

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i don`t know alfa

- #8

rachmaninoff

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- #10

rachmaninoff

A clear example:

(ED=3, EC=4, EB=5)

D----E------C

A------------B

Area of ADCB: 7*3=**21**

compare to:

E

D------------C

A----------- B

Area of ADCB: roughly**3.29**...

Thus, ED, EC, and EB do not uniquely specify an area for ADCB; you need alfa and beta also.

(ED=3, EC=4, EB=5)

D----E------C

A------------B

Area of ADCB: 7*3=

compare to:

E

D------------C

A----------- B

Area of ADCB: roughly

Thus, ED, EC, and EB do not uniquely specify an area for ADCB; you need alfa and beta also.

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- #11

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any other ideas, i hate to think that this task cannot be done

- #12

rachmaninoff

Area = (DC) * (CB)

[tex]=\left( 3^2+4^2-2 \cdot 3 \cdot 4 \cdot \cos (\alpha + \beta) \right) \left( 4^2+5^2-2 \cdot 4 \cdot 5 \cdot \cos (\alpha) \right)[/tex]

=...

As you see, it's dependent on both "alfa" and beta.

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B
Surface area problem -- Area of the circle enclosed by the current produced by an electron in a hydrogen atom

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