- #1
johnhuntsman
- 76
- 0
r2 = 4cos(2θ)
First I graph it. Then I set up the integral.
_____π
(1 / 2)∫ 4cos(2θ) dθ
_____0
________π
= [sin(2θ)]
________0
I thought the limits ought to be π and 0, but that comes out to zero. I pick other limits and they come out to 0. My graph matches the one in the back of the book. I know I've integrated correctly. I think the problem is the limits I'm picking somehow. The correct answer is 4.
[Edit] I also picked (π / 4) and -(π / 4) as limits, but that certainly didn't get me 4. [Edit]
First I graph it. Then I set up the integral.
_____π
(1 / 2)∫ 4cos(2θ) dθ
_____0
________π
= [sin(2θ)]
________0
I thought the limits ought to be π and 0, but that comes out to zero. I pick other limits and they come out to 0. My graph matches the one in the back of the book. I know I've integrated correctly. I think the problem is the limits I'm picking somehow. The correct answer is 4.
[Edit] I also picked (π / 4) and -(π / 4) as limits, but that certainly didn't get me 4. [Edit]