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Area under the curve

  1. Dec 5, 2009 #1
    how do you find the integral of the equation sqrt(36-.22x^2) between x=0 and x=9
  2. jcsd
  3. Dec 5, 2009 #2


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    Well, we have:

    And our integral may be rewritten as:

    Do you have any ideas how to proceed from here?
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