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Hello everyone am new to this forum my name is lucy and i hope i can help and get help from other i got this tutorial question that i seem to keep getting wrong :s i hope someone can help me :) the question is

Use a double integral to calculate the area of the region in the positive quadrant of the xy-plane bounded above by y=1, to the left by y= 1 -x and to the right by y=(1-x)^3

first i reaggare y=1-x and y=(1-x)^3 to get

x=1-y and x=y

to get the double integal that looks like this

[tex]\oint^{1}_{0}[/tex] [tex]\oint^{y^1/3 + 1}_{1-y}[/tex] 1 dx dy

= [tex]\oint^{1}_{0}[/tex] y^1/3 + 1 - 1 + y

= [3/4 y^4/3 + 1/2 y^2] between 1 and 0

= 4/9 + 1/2 - 0

= 17/18

Sorry for the mess am still trying to get a hang of this, am been at this question for ages am pretty bad at those but if any one could give a little bit of help it will be of a lot of help to me thanks alot :)

Use a double integral to calculate the area of the region in the positive quadrant of the xy-plane bounded above by y=1, to the left by y= 1 -x and to the right by y=(1-x)^3

first i reaggare y=1-x and y=(1-x)^3 to get

x=1-y and x=y

^{1/3}+ 1to get the double integal that looks like this

[tex]\oint^{1}_{0}[/tex] [tex]\oint^{y^1/3 + 1}_{1-y}[/tex] 1 dx dy

= [tex]\oint^{1}_{0}[/tex] y^1/3 + 1 - 1 + y

= [3/4 y^4/3 + 1/2 y^2] between 1 and 0

= 4/9 + 1/2 - 0

= 17/18

Sorry for the mess am still trying to get a hang of this, am been at this question for ages am pretty bad at those but if any one could give a little bit of help it will be of a lot of help to me thanks alot :)

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