Find the area of the regions shown in the figures. These are the graphs used : y = x^2 x = 2 Sin ^2 (y) I know that I need to set the two equations equal to each other in order to find the points of intersection, but I run into some trouble when trying to simplify it for y. This is what I tried Since y=x^2 Sqrt.(y)= x So now I have x= Sqrt.(y) x= 2 Sin ^2 (y) Sqrt.(y) - 2 Sin ^2 (y) = 0 So based on the graph that I am given in the book I can't really tell which is the top or right curve to subtract the bottom or left curve. After this step I would square both sides and be left with (Sqrt.(y) -2 Sin(^2y)^2) = 0, but I am not sure if that is allowed. Not sure on how to proceed from here. I would appreciate some help. Thanks!