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Three consecutive terms of an A.P. have a sum of 36 and a product of 1428. Find the three terms.

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- Thread starter tykescar
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- #1

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Three consecutive terms of an A.P. have a sum of 36 and a product of 1428. Find the three terms.

- #2

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you have the fact that a1 * a2 * a3 = 1428

and if d is the difference between a1-a2 and a2-a3,

then you have; a1* (a1 + d) * (a1 + 2d) = 1428

so that's the first piece of information. Do you think you could put the second piece of information in terms of a1 and d, and then you would have 2 variables and 2 equations.

- #3

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Brilliant. Thanks very much for your help.

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