1. Mar 25, 2009

### Timiop2008

I would really appreciate any help to figure out the following 4 questions:

1) The Sum of the first two terms of an arithmetic progression is 18 and the sum of the first four terms is 52. Find the sum of the First eight terms

2) An arithmetic Progression has first term a and common difference -1. The sum of the first n terms is equal to the sum of the first 3n terms. Express a in terms of n.

3) Find the sum of the arithmetic progression 1,4,7,10,13,16,...,1000.
Now find the sum if every third term is removed

4) In the Sequence 1.0,1.1,1,2...,99.1,100.0 each number after the first is 0.1 greater than the previous number. Find: 1) the number of number is the sequence and 2) the sum of the numbers in the sequence.

I don't think I know any of the relevent equations (If there are any that is)
Thankyou

2. Mar 25, 2009

### Staff: Mentor

DEFINITIONS!

What is it that makes a numeric progression an arithmetic progression as opposed to, say, a geometric progession?

3. Mar 25, 2009

### Timiop2008

An Arithmetic Progression is a sequence with a common difference eg 3,6,9,12,15 (with Common difference 3) whereas a Geometric Progression uses multipliers instead of a common difference i.e. x, x squared, x cubed,...

4. Mar 25, 2009

### Timiop2008

OK I've done the third question using a formula I found on wikipedia: n/2(a+l) where n is the number of terms, a is the first term and l is the last term.

First I found the number of terms by dividing by the common difference:

n= 1000/d
=1000/3
=333.3
=334

Then use the formula:

n/2(a+l)
=334/2(1+1000)
=167 X 1001
=167167

and for (part 2) I just multiplied by two thirds to remove a third of the terms (every third term):
167167 x (2/3) = 111444.67
=111445

I would appreciate any help on the other Q's guys . Thanks

5. Mar 25, 2009

### Staff: Mentor

So for problem 1, you have
a, a + d, a + 2d, a + 3d

With the given information you should be able to find a and d, and from that, the sum of the first 8 terms.

6. Mar 25, 2009

### Staff: Mentor

Correct, there are 334 terms. A better way to see this is to list them (or at least list enough of them to see the pattern).
1, 1 + 1*3, 1 + 2*3, 1 + 3*3, 1 + 4*3, ... , 1 + 333*3
The ellipsis (...) means "continuing in the same pattern."
That last term is equal to 1000, and starting from the 2nd term up to the last there are 333 terms, plus the one I didn't count at the beginning, for a total of 334 terms

Right.
You might be on shaky ground here. If you're off, and I don't know that you are, you won't be off by much. A better way to do it is to list the ones you're removing, say 7, 16, 25, and so on. This is also an arithmetic series, but with a different common difference. If you can list all of them (or at least a few at the beginning, an ellipsis, and the last one up around 1000, you can find its total, and subtract that from the number you got in the first part.

7. Mar 25, 2009

### Timiop2008

Thanks

I just need solutions for the first 2 Questions now.

I cannot even begin to attempt the second question (would really appreciate an help) but i tried this for the first question:

2n+d=18
4n+3d=52

So, Using simultaneous equations:

4x+3d=52
-4x+2d=36
d=16

I then put 16 into one of the equations to find x(or n) as 1.
So n=1, & d=16

For 8 terms, there will be 7 differences, so
8X1 + 7X16
=8+112
=120

Apparantly this is incorrect -the answer sheet says 168 but i don't know why!
Is there something I have overlooked?

PS. The answer to the second question is 2n-1\2 but i really don't know how to get this (I would greatly appreciate any help).
Thanks

8. Mar 26, 2009