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Arithmetic sequences

  1. Jan 25, 2006 #1
    1. Give an example of an arithmetic sequence such that the 35th term is 4,207?

    I used the general form of an arithmetic seq. an = a1 + (n-1)d and found that,

    a1 = 25, and d = 123

    Does this look ok? I had to use some trial and error since we have two unknowns.


    2. What is the 57th smallest whole number that has a remainder of 2 when it is divisible by 4 and 6.

    I am getting 686.


    3. Mark saved money in his bank. The first month he put 11$ in the bank. Every month thereafter he deposited more money, and it was the same amount each month. When he counted the money he totaled 195.00$ .What are possible amounts of money he could have deposited each month?

    Solution:
    Lets assume that he continued to deposit for m number of months after the first month. Also lets assume that he deposited x dollars each month.

    I am feeling something is missing in this problem. Anyway this is how I did this.

    195 = 11 + m * x

    m * x = 184
    x = 184/m where m is a whole number.

    The possible values of money deposited are 184/m where m = 1,2,3,4,………………….

    Some possible values for the money deposited are: $184, $92, $61.3, $46, ………..



    Thanks a lot,

    Gamma.
     
    Last edited: Jan 25, 2006
  2. jcsd
  3. Jan 25, 2006 #2
    All three look correct, though you may want to formulate #3 in terms of all factors of 18,400 (cents).
     
  4. Jan 25, 2006 #3

    HallsofIvy

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  5. Jan 25, 2006 #4
    For the first problem, you can as well take the first term as 4173 and the common difference as 1.
    i.e.
    a= 4173
    d = 1
    The arithmetic sequence in this case would be 4173,4174,4175.....4207.
    spacetime
    Physics
     
  6. Jan 25, 2006 #5

    NateTG

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    Isn't 2 the smallest whole number that has a remainder of 2 when it is divided by 4 or 6.
     
  7. Jan 25, 2006 #6
    Words can confuse. I thought 12 is the smallest whole number which satisefies our condition and 12 is therefore the first such whole number.

    Here are the numbers in ascending order

    12, 24, 36, ....................an

    an = 12n, for n= 57, a57 = 684

    57 th such number is 684+2 = 686. By the way this tutorial is on arith. series and so this solution make sense i guess.:rofl:

    HallsofIvy: I don't understand why you did what you did. Even if 24 is the smallest such number, then you should be getting an = 12(n+1)
    a57 = 696 and so the answer would have been 696+2= 698.


    Can there be a remainder when a smaller number is devided by a larger number?? 2/4 = 1/2??
     
  8. Jan 25, 2006 #7

    VietDao29

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    Why not? Let's think about it:
    2 = 0 x 4 + 2. So when 2 is divided by 4, 0 is the quotient, and 2 is the remainder... :wink:
    ------------------
    So in general, if n < p then when divinding n by p, you get 0 as the quotient, and n as the remainder.
     
  9. Jan 25, 2006 #8

    I am sure the man who wrote this problem did not think about it.


    While we are at this can I ask another question regarding sequences?

    What is meant by index and value of a sequence? Is index n and value an?

    This is the question: Using the index of a sequence as the domain and the value of the sequence as the range, is a sequence a function?

    I think the answer is yes.

    Thanks

    Gamma
     
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