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Isn't the Arrhenius law k=A*exp(-Ea/(R*T))? why can ln(rate) also be plotted vs T^-1 to find activation energy?

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- #1

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Isn't the Arrhenius law k=A*exp(-Ea/(R*T))? why can ln(rate) also be plotted vs T^-1 to find activation energy?

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Is it possible that some people refer to the rate constant simply as "rate?" Otherwise, the rate would have to be constant for the equation to apply.pwnzorz said:

Isn't the Arrhenius law k=A*exp(-Ea/(R*T))? why can ln(rate) also be plotted vs T^-1 to find activation energy?

Chet

An Arrhenius plot is a graphical representation of the Arrhenius equation, which describes the relationship between the rate of a chemical reaction and the temperature at which it occurs. It is used to determine the activation energy of a reaction.

To construct an Arrhenius plot, you will need to collect data on the rate of the reaction at different temperatures. Plot the natural logarithm of the rate (ln(k)) on the y-axis and the reciprocal of the temperature (1/T) on the x-axis. The slope of the resulting line is equal to the negative activation energy.

The activation energy is a measure of the minimum amount of energy required for a chemical reaction to occur. In an Arrhenius plot, it is represented by the slope of the line and can provide valuable information about the mechanism of the reaction and the stability of the reactants and products.

An Arrhenius plot is typically used for reactions that follow the Arrhenius equation, which describes the effect of temperature on the rate of a reaction. However, it may not be applicable for reactions with complex mechanisms or those that do not exhibit a clear temperature dependence.

To determine the rate constant (k) of a reaction from an Arrhenius plot, you can use the slope-intercept form of the equation: ln(k) = -Ea/R + ln(A), where Ea is the activation energy, R is the gas constant, and A is the pre-exponential factor. The value of k can be calculated using the slope and intercept of the line.

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