1. The problem statement, all variables and given/known data A 125 - G arrow is shot vertically upwards with a Vi of 28/ms. Assuming a 20% loss in Mechanical Energy while ascending, what maximum height above the position it was shot does it reach? 2. Relevant equations Vi= 28m/s Vf= O m/s D= ? a= -9.8 m/s Vf^2= Vi^2 + 2aD Eg = mgh Ek = 1/2mv^2 EM = Eg + Ek (not sure} 3. The attempt at a solution I did not really understand this question but I tried to make a solution using what I know. I tried using one of the 5 equations but that did not help so i tried using work and energy equations. So i did Ek first Ek= 1/2 mv ^2 Ek = 1/2 (0.125 kg) (28 m/s)^2 Ek = 98 J Next I tried finding the Eg Eg = Ek x 0.70 (30% loss of mechanical energy, this is what i am thinking) Eg = 68.6 J Eg = mgh Eg= 0.125 (9.8) h 68.6 = 1.225 h 68.6/1.225= h h= 55.51 m Did I do this question right or wrong? I am very confused. Some help would be appreciated!