- #1
Lil Uzi Vert
- 6
- 1
Homework Statement
A 125 - G arrow is shot vertically upwards with a Vi of 28/ms. Assuming a 20% loss in Mechanical Energy while ascending, what maximum height above the position it was shot does it reach?
Homework Equations
Vi= 28m/s
Vf= O m/s
D= ?
a= -9.8 m/s
Vf^2= Vi^2 + 2aD
Eg = mgh
Ek = 1/2mv^2
EM = Eg + Ek (not sure}
The Attempt at a Solution
I did not really understand this question but I tried to make a solution using what I know.
I tried using one of the 5 equations but that did not help so i tried using work and energy equations.
So i did Ek first
Ek= 1/2 mv ^2
Ek = 1/2 (0.125 kg) (28 m/s)^2
Ek = 98 J
Next I tried finding the Eg
Eg = Ek x 0.70
(30% loss of mechanical energy, this is what i am thinking)
Eg = 68.6 J
Eg = mgh
Eg= 0.125 (9.8) h
68.6 = 1.225 h
68.6/1.225= h
h= 55.51 m
Did I do this question right or wrong? I am very confused. Some help would be appreciated!