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Introductory Physics Homework Help
Arrow strike, Avg force, Conservation of energy
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[QUOTE="Sarah0001, post: 6252113, member: 653223"] [B]Homework Statement:[/B] The arrow is brought to rest in a distance of 5 mm, what is the average force of the arrow strike? [B]Relevant Equations:[/B] (1/2 )mv^2 = Fx F= mΔv/Δt The arrow is following projectile motion to the target when released from an archer's bow. v vertical = 10ms^-1 v horizontal = 50 ms^-1 resultant v = √2600 mass of arrow = 20*10^-3 I attempted to use F avg = mΔv/Δt to calcualte the average force where Δt = 5*10^-3 / √2600 u = √2600 v = 0 then plugging these in I get an answer of 10400N twice that of the actual answer. The solution uses the conversation of energy: ΔKE = Fx all of arrows KE is importated to the target, the arrow does work over a distance of 5mm to bring itself to rest, so loss of KE = work done by arrow on the target. I understand this is true, but Q1) what is wrong with using F avg = mΔv/Δt to calculate the average force of the arrow exerts.Q2 What am I wrongly assuming by using this formula? and Q3)why doesn't it apply here? [/QUOTE]
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Introductory Physics Homework Help
Arrow strike, Avg force, Conservation of energy
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