Monoxdifly said:A die is tossed 100 times. What's the expected frequency that the number appears will be 4?
The probability is 1/6, so the expected frequency is 1/6 × 100, but that results in a fraction (16 2/3). Do we need to round it up or down? Is the answer 16 or 17?
The probability of getting exactly four 4s in 100 tosses is approximately 0.0023, or 0.23%. This can be calculated using the binomial probability formula, where n = 100 (number of trials), p = 1/6 (probability of getting a 4 on each toss), and k = 4 (desired number of successes).
The probability of getting at least one 4 in 100 tosses is approximately 0.5175, or 51.75%. This can be calculated by subtracting the probability of getting zero 4s from 1. The probability of getting zero 4s can be calculated using the binomial probability formula with n = 100, p = 1/6, and k = 0.
We can expect to see approximately 16.67 4s in 100 tosses. This can be calculated by multiplying the number of tosses (100) by the probability of getting a 4 on each toss (1/6).
Yes, it is possible to get more than four 4s in 100 tosses. While the probability of getting exactly four 4s is low, there is still a chance of getting more than four 4s in 100 tosses. In fact, the probability of getting five or more 4s in 100 tosses is approximately 0.0005, or 0.05%.
The probability of getting a 4 in 100 tosses will increase as the number of tosses increases. This is because with more tosses, there are more opportunities for a 4 to appear. However, the probability will never reach 100%, as there is always a chance that a 4 will not appear in any given toss.