Assignment due in less than 1 hr

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In summary, the conversation is about someone seeking help with a question involving two blocks and two pulleys. The person is having trouble understanding the system and asks for a picture, but is unable to post it. Another person suggests starting with the equation \sum{F} = ma and drawing a free body diagram to solve for T. The conversation ends with the suggestion to do the same for the next part of the question.
  • #1
disruptors
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Hey ppl, sorry I was just wondering if anyone knew how to do the question i posted earlier(TWO BLOCKS AND TWO PULLEYS), as I have to submit it and cannot figure it out still!?

Thanks...
 
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  • #2
can you post a picture of it. I'm having trouble picturing this system.
 
  • #3
here's the pic, thanks
 
  • #4
where? I don't see it as part of your post
 
  • #5
oh sorry tiger, its okay i had to submit it, thanks for your time...i can't get the pic up for some reason..
 

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  • #6
never mind must have been my browser
 
  • #7
well how did you do the first part? it looks right to me. you did:

[tex]\sum{F} = ma[/tex]

always always ALWAYS start with this over and over again (or at least try to strat with this). The right hand side will have only ma or 0 that's all it will ever have ( and zero is a particular case of ma--when it is not accelarating, that is, not moving, or constant velocity) The left hand side just sums your forces. So after picking your postitive and negnative on your x and y-axis (always do this too) and drew your free body diagram (I hop you did this) you must of did:

[tex]T + T = m_2a_2[/tex]

And then you solved for T

Now for the next part do the same thing

1) Draw FBD
2) [tex]\sum{F} = ma[/tex]
3) [tex]T - m_1g = m_1a_1[/tex]

And then solve for [tex]a_1[/tex] in terms of everything else they gave you
 
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