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Assignment question

  1. Oct 22, 2006 #1
    assignment question URGENT!!!!!!!!!!!!!

    I having trouble and its urgent some one help
    Triangle wit the vertices A(6,-15)B(22,17)and C(24,11)

    -midpoint of side A = (14,1)


    1.Calculate the equation of the line that is perpindicular bisector of the side triangle.
  2. jcsd
  3. Oct 22, 2006 #2
    Use the fact that [tex] m_{2} = -\frac{1}{m_{1}} [/tex] for a perpendicular line.
  4. Oct 22, 2006 #3
    i Still do not get it
    Last edited: Oct 22, 2006
  5. Oct 22, 2006 #4
    but how do i figure out the equation of the line
  6. Oct 22, 2006 #5
    Bump Bump Bump
  7. Oct 22, 2006 #6
    The slope of [tex] AB [/tex] is [tex] 2 [/tex]. So the slope of the perpendicular bisector is [tex] -\frac{1}{2} [/tex].

    So use the equation [tex] y-y_{1} = m(x-x_{1}) [/tex].

    So [tex] y - 1 = -\frac{1}{2}( x-14) [/tex]
    Last edited: Oct 22, 2006
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