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I can find all factors of 180 and all multiples of 6 and compare, but that is not the mathematical way. I dont have a concrete idea how to start so any assistance would be more than enough.

Thanx.

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- Thread starter Petkovsky
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- #1

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I can find all factors of 180 and all multiples of 6 and compare, but that is not the mathematical way. I dont have a concrete idea how to start so any assistance would be more than enough.

Thanx.

- #2

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- #3

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So, we can take (2*3) *2 = 6*2 =12 which is a multiple of 6 and a factor of 180.

Next, take the prime factors 2*3 * 3 = 6*3 = 18. Thus, it is a multiple of 6 and a factor of 18.

Continue, you see a pattern i.e. (2*3)*5, (2*3)*3*3... of permutations.

- #4

tiny-tim

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I can find all factors of 180 and all multiples of 6 and compare, but that is not the mathematical way. I dont have a concrete idea how to start so any assistance would be more than enough.

Thanx.

Hi Petkovsky!

Hint: if 6n is a factor of 180,

that

and so … ?

- #5

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Thank you :)

- #6

tiny-tim

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(delete it if you still can)

(i'm not sure it's right anyway …)

Just give hints.

- #7

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6*2*3*5

Yes, my answer wasn't correct actually :D

6*2, 6*3, 6*5

Maybe this is correct.

Yes, my answer wasn't correct actually :D

6*2, 6*3, 6*5

Maybe this is correct.

- #8

tiny-tim

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Homework Helper

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6*2*3*5

Yes, my answer wasn't correct actually :D

6*2, 6*3, 6*5

Maybe this is correct.

Physicsissuef, what part of

You

Well … you're obviously just guessing now … so no harm done!

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