r = 6400 km how much less does a 100kg person weigh at the equator than at the poles because of the rotation of the earth? Ok I have figured out that g(equator) is .03 m/s^2 less than it is at the poles due to the rotation on the earth. so F(pole) = (100kg)(g) and F(equator) = 100kg(g - .03m/s^2) My question is what should be the value for g in this case? If i make g = 9.8, then it will be 9.77 at the equator or should it be g = 9.83 ... making it 9.80 at the equator. not a big difference, but I'm just wondering which one is correct.