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Asteroid orbit physics problem

  1. Mar 22, 2010 #1
    An asteroid is orbiting around the sun at a distance of 4.2x 1011 m. If the Earth orbits around the Sun at a distance of 1.5 x 1011 m with a period of 3.2 x107 s, what is the period of the asteroid?

    Im thinking it was 9.0 x 10^7 s ?
     
  2. jcsd
  3. Mar 22, 2010 #2

    mgb_phys

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    Re: Asteroid

    Do you have a reason for thinking that?
    Is it the same reason that Kepler had?
     
  4. Mar 22, 2010 #3
    Re: Asteroid

    use kepler's laws. R^3/T^2 is always constant when orbiting the same parent body.
     
  5. Mar 22, 2010 #4
    Re: Asteroid

    Hello,

    So it would be (1.5x10^11) ^3 / (3.2 x10^7) ?
     
  6. Mar 22, 2010 #5
    Re: Asteroid

    Hello,

    So it would be (1.5x10^11) ^3 / (3.2 x10^7) ?
     
  7. Mar 22, 2010 #6
    Re: Asteroid

    An asteroid is orbiting around the sun at a distance of 4.2x 1011 m. If the Earth orbits around the Sun at a distance of 1.5 x 1011 m with a period of 3.2 x107 s, what is the period of the asteroid?

    Im thinking it was 9.0 x 10^7 s ?

    (4.2x10^11)^3/(t^2) = (1.5x10^11)^3/(3.2x10^7)^2

    I'm looking at 1.5x10^8 sec.
     
  8. Mar 22, 2010 #7
    Re: Asteroid

    Ooo I get it now! wow, thank you soo much :):):) I don't know how I didn't see that from the beginning
     
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