- #1

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The asteroid belt circles the sun between the orbits of Mars and Jupiter. One asteroid has a period of 5 earth years. What is the asteroid's orbital radius and speed?

Thanks!!!

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- Thread starter guru
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- #1

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The asteroid belt circles the sun between the orbits of Mars and Jupiter. One asteroid has a period of 5 earth years. What is the asteroid's orbital radius and speed?

Thanks!!!

- #2

- 574

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[tex]T=\frac{2\pi r^{\frac{3}{2}}}{\sqrt{Gm_{sun}}}[/tex]

where G is the universal gravitational constant and T is the orbital period.

- #3

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will the period be 31536000s. if it is, is this right:Sirus said:

[tex]T=\frac{2\pi r^{\frac{3}{2}}}{\sqrt{Gm_{sun}}}[/tex]

where G is the universal gravitational constant and T is the orbital period.

r=[T*(sqrt(GM_sun)/2pi)]^(2/3)

[ 31536000*sqrt(6.67*10^(-11)*(1.99*10^(30)))/(2*pi)]^(2/3)

- #4

- 574

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Check your period calculation again. Your method looks correct.

- #5

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oppsSirus said:Check your period calculation again. Your method looks correct.

31536000*5?

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