Asteroid's orbital radius and speed

  • Thread starter guru
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  • #1
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somebody help me start this question

The asteroid belt circles the sun between the orbits of Mars and Jupiter. One asteroid has a period of 5 earth years. What is the asteroid's orbital radius and speed?

Thanks!!!
 

Answers and Replies

  • #2
574
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I believe you need the mass of the sun, unless you are allowed to give your answer as a function of that variable. Use this formula:
[tex]T=\frac{2\pi r^{\frac{3}{2}}}{\sqrt{Gm_{sun}}}[/tex]
where G is the universal gravitational constant and T is the orbital period.
 
  • #3
38
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is this right

Sirus said:
I believe you need the mass of the sun, unless you are allowed to give your answer as a function of that variable. Use this formula:
[tex]T=\frac{2\pi r^{\frac{3}{2}}}{\sqrt{Gm_{sun}}}[/tex]
where G is the universal gravitational constant and T is the orbital period.
will the period be 31536000s. if it is, is this right:
r=[T*(sqrt(GM_sun)/2pi)]^(2/3)
[ 31536000*sqrt(6.67*10^(-11)*(1.99*10^(30)))/(2*pi)]^(2/3)
 
  • #4
574
2
Check your period calculation again. Your method looks correct.
 
  • #5
38
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Sirus said:
Check your period calculation again. Your method looks correct.
opps
31536000*5?
 

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