# Astro, p-p process

1. Nov 12, 2007

### Qyzren

H1 means hydrogen with mass 1, H2 means hydrogen with mass 2 (has a neutron), etc

1) H1 + H1 -> H2 + positron + neutrino + 1.18 Mev (+0.26MeV)
2) H1 + H2 -> He3 + photon + 5.49MeV
3) He3 + He3 -> He4 + 2*H1 + 12.86 MeV

(The neutrino produced in 1 for all practical purposes do not interact with matter, so their energy can be ignored (neutrino energy 0.26MeV)

Using the above 3 equations, calculate the energy released per proton. Note that the equations must be properly combined in order to find the overall reaction! Given the sun's luminosity calculate the amount of hydrogen converted to helium every second. How much mass per second is converted directly to energy?

2. Relevant equations
sun's luminosity: 3.826*10^26 W

answers: 6.55 MeV, 6.2*10^11 kg, 4.3x10^9 kg.

3. The attempt at a solution

I have shown each proton has released 6.55 MeV. but how do i calculate the amount of hydrogen converted to helium every second?

Last edited: Nov 12, 2007
2. Nov 12, 2007

### dynamicsolo

(I removed part of my reply, since I missed at first where you said you'd gotten the 6.55 MeV per proton.)

Having gotten that answer, you have the energy release (in MeV) from one pp-reaction. Given what the luminosity (power output) of the Sun is, how many of these reactions would be needed per second? How many protons cease to exist as individuals and become groups of four in nuclei every second? How much mass is that?

Last question -- Since you have the Sun's luminosity, what mass is that energy equivalent to (that will take you from, say, Joules per second to kg/sec)? What famous equation might you use?

Last edited: Nov 12, 2007
3. Nov 12, 2007

### Qyzren

part c i've got, directly using E = mc² gives 4.3*10^9 kg

but i still have trouble with part b :(

Luminosity of sun is 3.826*10^26 W which is 3.826*10^26 J/s
6.55 MeV = 1.049 * 10^-12 protons/J .

Last edited: Nov 12, 2007
4. Nov 12, 2007