- #1

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I can't find a way to start off this problem. I drew a diagram and everthing.

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- #1

- 69

- 0

I can't find a way to start off this problem. I drew a diagram and everthing.

- #2

Homework Helper

- 1,509

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- #3

- 69

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The total momentum before the toss = 0 because there is no velocity.

After the toss,

P

- #4

- 2,093

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Resolve the momenta into components.

- #5

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Resolve the momenta into components.

m

like that?

- #6

- 2,093

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Nope, along the x and y axes.m_{tot}v_{tot}=m_{astro}v_{astro}+m_{tank}v_{tank}+m_{cam}v_{cam}

like that?

Since the total momentum is conserved, they must be conserved along the axes, too. So

initial momentum along x-axis = final momentum along x axis. Similarly for y.

- #7

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y: m

i think this is what you mean right?

- #8

- 2,093

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Yes, that's right.

Make sure you get the signs right when putting in the values of the velocities.

Make sure you get the signs right when putting in the values of the velocities.

- #9

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Yes, that's right.

Make sure you get the signs right when putting in the values of the velocities.

ok, so I'm solving for the velocity of the camera but i don't have the total momentum, so how can i solve for the camera's velocity with two unknowns?

- #10

- 2,093

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- #11

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Total momentum, and then the final velocity for the camera.

Can i say

-m

- #12

- 2,093

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Sure you can. The initial momenta along both directions is zero, remember?

- #13

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Sure you can. The initial momenta along both directions is zero, remember?

right, but i thought i was solving for the final velocity

- #14

- 2,093

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Yes you are. It is because of the zero initial momentum (mright, but i thought i was solving for the final velocity

- #15

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can u say ( also have this problem, and this is how i was working it out)

**m_ast*v_ast*cos(200) + m_tank*v_tank + m_cam*****v_cam***cos(20) = 0

these two equation actualy equal each other (produce same answer)

**-mavax=mcvcamx+mtankvtankx**

all withrespect to the x axis

can someone explain...

why do you have to use the y-axis or even worry about the x-axis in this problem... you can relate teh whole thing to the x component w/ trig?

x: mtvtx=mavax+mcvcx+mtankvtankx

**y: mtvty=mavay+mcvcy**

these two equation actualy equal each other (produce same answer)

all withrespect to the x axis

can someone explain...

why do you have to use the y-axis or even worry about the x-axis in this problem... you can relate teh whole thing to the x component w/ trig?

x: mtvtx=mavax+mcvcx+mtankvtankx

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