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My problem asks to find the vertical asymptotes of x^3/(x^2+3x-10)

I found –5 & 2 to be vertical asymptotes but what I can’t figure out is

how as x->-5- = -oo and x->-5+ = +oo

I have calculated lim x->-5+ x^3/(x^2+3x-10) = -125/(0)(-5 - -2) = -125/-0 = +oo

But I don’t see –oo lim x->+5+ x^3/(x^2+3x-10) = ???????????????

Can you show me the algebra and how the signs work out to give me –oo

Thanks

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# Homework Help: Asymptote Problem

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