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Asymptotic expansion integral

  1. Nov 29, 2006 #1

    Clausius2

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    Hey guys,
    I need help with the expansion of this integral:

    [tex]\int_0^\infty Z(x) J_o(\lambda x)dx[/tex] for [tex]\lambda \rightarrow \infty[/tex]

    where I know that [tex]Z(x)\sim x^\sqrt{2}[/tex] for small [tex]x[/tex] and
    exponentially small for large [tex]x[/tex]

    It seems with other examples that I have done that the major contribution to the integral comes from the region [tex]x\sim 1/\lambda[/tex]. For larger [tex]x[/tex] the integrand oscillates rapidly and the integration cancels. One change of variable (re-scaling) that you may try is [tex]t=\lambda x[/tex]. But if you do it you end up with a divergent integral. And at first glance the original integral is convergent. Any hints?

    Thanks.
     
    Last edited: Nov 29, 2006
  2. jcsd
  3. Nov 29, 2006 #2

    Clausius2

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    with divergent integral I mean that I arrive to this integral after the rescalement:

    [tex]\frac{1}{\lambda^{\sqrt{2}+1}}\int_0^\infty t^{\sqrt{2}} J_o(t)dt[/tex]
     
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