Asymptotic form of a wave function

In summary, the conversation discusses a physics assignment that involves numeric integration and the taylor expansion of a function. The conversation mentions using the definition of the derivative to obtain the taylor expansion and finding the asymptotic form of the wave function for a given potential. The student asks for hints on finding the initial asymptotic form.
  • #1
iamalexalright
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Homework Statement


For one of my physics assignments I need to do some numeric integration (and I know its physics but my question doesn't pertain to that).

Given
[itex]\hat{H}\Phi = E\Phi[/itex]
[itex]\frac{\delta^{2}\Phi}{\delta x^{2}}(x) = \frac{-2m}{h^{2}}(E - V(x))\Phi(x) = -Z(x)\Phi(x)[/itex]

We have the taylor expansion:
[itex]\Phi(x + 2d) = \Phi(x) + 2d\frac{\delta \Phi}{\delta x} + 2d^{2}\frac{\delta^{2}\Phi}{\delta x^{2}}[/itex]

Using definition of the derivative:
[itex]\frac{\delta \Phi(x)}{\delta x} = lim_{d\rightarrow 0} \frac{\Phi(x + d) - \Phi(x - d)}{2d}[/itex]

we can obtain:
[itex]\Phi(x + 2d) = \Phi(x + d) + \Phi(x) - \Phi(x - d) - 2d^{2}Z(x)\Phi(x)[/itex].

For the potential V(x) = Ax with A = -1, m = 1, h = 1, and E = 0, find the asymptotic form of the wave function for x >> 0. Use this form to find the three initial points.


This is where I run into problems. Maybe I'm missing something very obvious but I don't know how to find this initial asymptotic form. Any hints?
 
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  • #2
Homework Equations None really, just the ones listed above.The Attempt at a Solution I've tried rewriting the equations in different ways but I don't know where to go from here.
 

What is the asymptotic form of a wave function?

The asymptotic form of a wave function refers to the behavior of a wave function as it approaches infinity. It describes how the wave function behaves at very large distances from the origin.

Why is the asymptotic form of a wave function important?

The asymptotic form of a wave function is important because it can provide valuable information about the properties of a system. It can help us understand the behavior of particles at large distances and provide insights into the quantum mechanical nature of the system.

How is the asymptotic form of a wave function determined?

The asymptotic form of a wave function is determined by solving the Schrödinger equation for a particular system. This involves using mathematical techniques such as perturbation theory or numerical methods to find the wave function at large distances.

What are some common asymptotic forms of wave functions?

Some common asymptotic forms of wave functions include plane waves, spherical waves, and Coulomb waves. These forms are often used to describe the behavior of particles in different physical systems.

How does the asymptotic form of a wave function relate to the uncertainty principle?

The asymptotic form of a wave function is related to the uncertainty principle in that it can give us information about the momentum and position of a particle. The uncertainty principle states that the more precisely we know the position of a particle, the less precisely we know its momentum, and vice versa. The asymptotic form of a wave function can help us understand the relationship between these two quantities.

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