- #1
Kali8972
- 14
- 0
I was wondering if someone could help get me started on this problem. I thought I knew how to solve it but keep coming up with the wrong answer:
A 2.9 µC is at x = 0 and a -2.0 µC charge is at x = 3.5 cm. (Let V = 0 at r = .)
(a) At what point along the line joining them is the electric field zero?
x = cm
(b) At what points is the potential zero?
x = cm (smaller x value)
x = cm (larger x value)
a) [(2.9e-6 C)k]/(.055+ x)^2 = [k(2e-6)]/(x^2)
k's cancel.. and then use quadratic to find it but the values aren't the right ones... What am I missing?
Any help would be appreciated!
Thanks!
A 2.9 µC is at x = 0 and a -2.0 µC charge is at x = 3.5 cm. (Let V = 0 at r = .)
(a) At what point along the line joining them is the electric field zero?
x = cm
(b) At what points is the potential zero?
x = cm (smaller x value)
x = cm (larger x value)
a) [(2.9e-6 C)k]/(.055+ x)^2 = [k(2e-6)]/(x^2)
k's cancel.. and then use quadratic to find it but the values aren't the right ones... What am I missing?
Any help would be appreciated!
Thanks!