At what points is the potential zero?

  • Thread starter Kali8972
  • Start date
  • #1
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I was wondering if someone could help get me started on this problem. I thought I knew how to solve it but keep coming up with the wrong answer:

A 2.9 µC is at x = 0 and a -2.0 µC charge is at x = 3.5 cm. (Let V = 0 at r = .)

(a) At what point along the line joining them is the electric field zero?
x = cm
(b) At what points is the potential zero?
x = cm (smaller x value)
x = cm (larger x value)


a) [(2.9e-6 C)k]/(.055+ x)^2 = [k(2e-6)]/(x^2)

k's cancel.. and then use quadratic to find it but the values aren't the right ones... What am I missing???

Any help would be appreciated!!!
Thanks!!
 

Answers and Replies

  • #2
Tom Mattson
Staff Emeritus
Science Advisor
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Kali8972 said:
a) [(2.9e-6 C)k]/(.055+ x)^2 = [k(2e-6)]/(x^2)

Your problem is that you've got the [itex]2.9\mu C[/itex] charge sitting at x=-0.55cm, and you've got the [itex]-2\mu C[/itex] charge sitting at the origin.

(edited for typos)
 
  • #3
14
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well yeah I guess that would make things a little more difficult! haha thanks!!!
 

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