- #1

- 8

- 0

So, does atmoshperic pressure exist even on surfaces that are not in contact with the atmosphere, meaning in closed areas above.

Thank you.

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter l33t_V
- Start date

- #1

- 8

- 0

So, does atmoshperic pressure exist even on surfaces that are not in contact with the atmosphere, meaning in closed areas above.

Thank you.

- #2

Astronuc

Staff Emeritus

Science Advisor

- 19,819

- 3,280

If air volume in the tank has the same density (and temperature) as the atmosphere at sea-level, then it would have the same pressure. Normally water storage tanks are vented to the atmosphere, so as to preclude compression or decompression of the gas above the water surface.Hello all, i would like to know if atmospheric pressure exists on the surface of water in a completely sealed water tank.

So, does atmoshperic pressure exist even on surfaces that are not in contact with the atmosphere, meaning in closed areas above.

In a sealed water tank, the pressure in the gas above the water will increase or decrease with the level of the water. In the volume of gas, the pressure is taken as constant throughout the gas - assuming it's a relatively small volume or dρ/dz ~ 0. In water the pressure will increase with depth because the mass of water above a given elevation (depth) increases with depth.

- #3

- 2,483

- 100

- #4

- 8

- 0

So if we have a tank of height H, and we fill it with water with height h and then we close it tightly so it won't have contact with the atmosphere and assuming that a point A exists in the bottom of this sealed tank. What will be the pressure (under normal conditions) at that point A at the bottom ?

Is it P(A) =Patm + Density(W)*g*h

or simply P(A)=Density(W)*g*h ?

- #5

Astronuc

Staff Emeritus

Science Advisor

- 19,819

- 3,280

Assuming the air volume in the tank has contact (e.g., is vented) and the tank is filled to height h, then the vent is closed and no more water added, then the air pressure is still 1 atm, and the pressure at A at depth h is just

So if we have a tank of height H, and we fill it with water with height h and then we close it tightly so it won't have contact with the atmosphere and assuming that a point A exists in the bottom of this sealed tank. What will be the pressure (under normal conditions) at that point A at the bottom ?

Is it P(A) =Patm + Density(W)*g*h

or simply P(A)=Density(W)*g*h ?

Patm + ρgh, were ρ is the density of water.

If however, the valve is closed during the filling process, the air would be compressed and one would have to calculate the air pressure by the ratio of the volume at Patm to the volume once the tank is filled. In other words, if the volume of air decreases by a factor of 2, the pressure increases by a factor of 2 (Boyle's law). This of course assumes the gas is ideal, i.e., pV = k = nRT, or p

- #6

- 4,662

- 5

Bob S

Share: